M25 Lap - difference in distance clockwise vs anticlockwise.
Discussion
Here's one for you:
I had a couple of places to visit yesterday and ended up driving around the M25 and did a whole clockwise lap in the end. Towards the final stint I realised that if I had gone anti clockwise then my lap would have been shorter!
So then I started wondering: How much shorter is an anticlockwise lap versus a clockwise lap?
I have managed to get the answer and no doubt a lot of you will too.
So, anyone care to venture a guess?
I had a couple of places to visit yesterday and ended up driving around the M25 and did a whole clockwise lap in the end. Towards the final stint I realised that if I had gone anti clockwise then my lap would have been shorter!
So then I started wondering: How much shorter is an anticlockwise lap versus a clockwise lap?
I have managed to get the answer and no doubt a lot of you will too.
So, anyone care to venture a guess?
mrmr96 said:
Podie said:
mrmr96 said:
Podie said:
Half a mile difference between inside lanes, IIRC
Not bad.Anyone else got a guess?
I ran a data logging vehicle... if you want to get proper geeky, the length of the lanes varies as well due to slightly different incline rates...
Podie said:
mrmr96 said:
Podie said:
mrmr96 said:
Podie said:
Half a mile difference between inside lanes, IIRC
Not bad.Anyone else got a guess?
I ran a data logging vehicle... if you want to get proper geeky, the length of the lanes varies as well due to slightly different incline rates...
I didn't take account of the bridge/tunnel or the incline rates. I do like that incline rates point. (Where's the paperbag smilie.)
mrmr96 said:
Podie said:
mrmr96 said:
Podie said:
mrmr96 said:
Podie said:
Half a mile difference between inside lanes, IIRC
Not bad.Anyone else got a guess?
I ran a data logging vehicle... if you want to get proper geeky, the length of the lanes varies as well due to slightly different incline rates...
I didn't take account of the bridge/tunnel or the incline rates. I do like that incline rates point. (Where's the paperbag smilie.)
C'mon then, what did you get..?
Googlemaps is no help, says 118 miles for both, but saying the circumference of the nearside lane clockwise is 118 miles and each lane is 3 metres wide and same again for the dividing barrier in the middel, then that makes the the offside lane of the anti-clockwise lane a radius 18 metres less than the nearside lane of the clockwise one.
As we know the circumference of the clockwise one, we can work out its average radius as follows:
c = 2x pi x radius, so 118 = 2 x 3.147 x r, therefore r = 118/(2x3.147) or 18.7 miles (29,997 meters).
So, using the radius of the nearest lane to the centre, the circumference is 2 x 3.147 x (29,997-18) or 117.93 miles.
So, the answer is the the inner most lane is 0.07 miles shorter than the outer most lane if the above assumpitions on lane width are correct, there are only 3 lanes on each side and excluding any points where the carriageways diverge (tunnels, QE2 bridge,etc).
As we know the circumference of the clockwise one, we can work out its average radius as follows:
c = 2x pi x radius, so 118 = 2 x 3.147 x r, therefore r = 118/(2x3.147) or 18.7 miles (29,997 meters).
So, using the radius of the nearest lane to the centre, the circumference is 2 x 3.147 x (29,997-18) or 117.93 miles.
So, the answer is the the inner most lane is 0.07 miles shorter than the outer most lane if the above assumpitions on lane width are correct, there are only 3 lanes on each side and excluding any points where the carriageways diverge (tunnels, QE2 bridge,etc).
Edited by youngsyr on Thursday 14th May 16:58
youngysr, you're nearly there but if you use more algebra you get a better answer (IMO).
r(a) = radius anti clockwise
r(c) = radius clockwise
c(a) = circumference anti clockwise
c(c) = circumference clockwise
c(a) = 2 * pi * r(a)
c(c) = 2 * pi * r(c)
A standard lane is 3.6m wide. So, assuming 3 lanes each way, plus 3.6m for the central reservation means there are 6 x 3.6m between the middle of lane one on each carriageway. Which is 21.6 meters.
So r(c)=r(a)+21.6
So:
c(c)-c(a)= (2 * pi * r(c)) - (2 * pi * r(a))
= 2 * pi * (r(c)-r(a))
= 2 * pi * (r(a)+21.6-r(a))
= 2 * pi * 21.6
= 135.7 meters
= 0.08 miles
(pi is approx 3.14159265 btw)
r(a) = radius anti clockwise
r(c) = radius clockwise
c(a) = circumference anti clockwise
c(c) = circumference clockwise
c(a) = 2 * pi * r(a)
c(c) = 2 * pi * r(c)
A standard lane is 3.6m wide. So, assuming 3 lanes each way, plus 3.6m for the central reservation means there are 6 x 3.6m between the middle of lane one on each carriageway. Which is 21.6 meters.
So r(c)=r(a)+21.6
So:
c(c)-c(a)= (2 * pi * r(c)) - (2 * pi * r(a))
= 2 * pi * (r(c)-r(a))
= 2 * pi * (r(a)+21.6-r(a))
= 2 * pi * 21.6
= 135.7 meters
= 0.08 miles
(pi is approx 3.14159265 btw)
Edited by mrmr96 on Thursday 14th May 16:52
mrmr96 said:
youngysr, you're nearly there but if you use more algebra you get a better answer (IMO).
r(a) = radius anti clockwise
r(c) = radius clockwise
c(a) = circumference anti clockwise
c(c) = circumference clockwise
c(a) = 2 * pi * r(a)
c(c) = 2 * pi * r(c)
A standard lane is 3.6m wide. So, assuming 3 lanes each way, plus 3.6m for the central reservation means there are 6 x 3.6m between the middle of lane one on each carriageway. Which is 21.6 meters.
So r(c)=r(a)+21.6
So:
c(c)-c(a)= (2 * pi * r(c)) - (2 * pi * r(a))
= 2 * pi * (r(c)-r(a))
= 2 * pi * (r(a)+21.6-r(a))
= 2 * pi * 21.6
= 135.7 meters
= 0.08 miles
(pi is approx 3.14159265 btw)
You worked it out exactly the same way as me, mate just using a more accurate lane width (3.6m as opposed to 3m) and you got the correct number for pi, for some reason I thought it was 3.147!r(a) = radius anti clockwise
r(c) = radius clockwise
c(a) = circumference anti clockwise
c(c) = circumference clockwise
c(a) = 2 * pi * r(a)
c(c) = 2 * pi * r(c)
A standard lane is 3.6m wide. So, assuming 3 lanes each way, plus 3.6m for the central reservation means there are 6 x 3.6m between the middle of lane one on each carriageway. Which is 21.6 meters.
So r(c)=r(a)+21.6
So:
c(c)-c(a)= (2 * pi * r(c)) - (2 * pi * r(a))
= 2 * pi * (r(c)-r(a))
= 2 * pi * (r(a)+21.6-r(a))
= 2 * pi * 21.6
= 135.7 meters
= 0.08 miles
(pi is approx 3.14159265 btw)
Edited by mrmr96 on Thursday 14th May 16:52
The methodology is identical and equally open to inaccuracy in its assumptions, particularly the variation in lane width of between 2 and 8 lanes in places.
Gassing Station | General Gassing | Top of Page | What's New | My Stuff