0 to 60mph..........0 to100mph figures
Discussion
dhf said:
i am probably having one of those evenings but can anyone help ? if a car covers 70 yards in the 0-60mph dash how many seconds did it take ? likewise 0-100mph in 250 yards,how many seconds did it take ? much appreciated any help with formula to work it out.
If you could assume constant acceleration, you could work it out because the average speed is half the terminal speed and distance divided by average speed gives you time. Since the acceleration is not a constant, there is no single answer. You could have one car that accelerates instantly to 59 mph and then cruises until it gets to the line, or one that goes at a snails pace over the first 69 yards and then accelerates to 60 mph at the last moment. Both would cover the same distance and end up at the same speed but the time taken would be radically different.Edited by GreenV8S on Saturday 24th May 22:11
As said aceleration would need to be linear to work it out with your data.
But in the interest of encourging our kids to learn MATHS!
60MPH = 1760 yards a minute = 29.3 yards a second.
But due as our aceleration is linear for this example we divide by 2 = 14.7 yards per second.
So 70 divided by 14.7 =4.8 seconds. NOT BAD!!
Now can you do the second equation???
But in the interest of encourging our kids to learn MATHS!
60MPH = 1760 yards a minute = 29.3 yards a second.
But due as our aceleration is linear for this example we divide by 2 = 14.7 yards per second.
So 70 divided by 14.7 =4.8 seconds. NOT BAD!!
Now can you do the second equation???
Steve E said:
As said aceleration would need to be linear to work it out with your data.
But in the interest of encourging our kids to learn MATHS!
... and a bit of physicsBut in the interest of encourging our kids to learn MATHS!
s = ut + 1/2at2
where s = distance, u is original velocity, t=time involved, a = acceleration - presumes linear acceleration as said above
Ubernoober said:
Steve E said:
As said aceleration would need to be linear to work it out with your data.
But in the interest of encourging our kids to learn MATHS!
... and a bit of physicsBut in the interest of encourging our kids to learn MATHS!
s = ut + 1/2at2
where s = distance, u is original velocity, t=time involved, a = acceleration - presumes linear acceleration as said above

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