Any Regex wizards on here?

[StephenP]

I'm not sure if this is even possible with a regex but I'm trying to test if a string contains a minimum number of a specific character.

For example, if I want 3 or more '1's in the text to equal true...

1100000000000000 = false
1000101000000000 = true
1111111111111111 = true

If possible, I'm trying to avoid changing some code that already has a test in place where the variable and Regex values are both passed in to the program.

Google hasn't helped with my basic Regex skills!

[EddieSteadyGo]

I'd use ChatGPT for that type of question. You can create a free account and still get access to GPT4-o which is the latest model.

Just pasting your exact post gives the following response. With some finessing I think you could get exactly what you need.

https://chatgpt.com/share/df477631-3179-454d-a11e-...

Also worth trying Claude Sonnet, which is another LLM. I've found it better than ChatGPT on a number of occasions.

https://claude.ai/new

[danpalmer1993]

I think this should work but it's been a while since I did any regex.

^(?:[^1]*1){3}[^1]*$

[StephenP]

That works perfectly! Never even thought of using ChatGPT to generate it so thanks for the suggestion

[tribbles]

danpalmer1993 said:

I think this should work but it's been a while since I did any regex.

^(?:[^1]*1){3}[^1]*$

Seems a bit complicated, unless I'm missing something...

1.*1.*1

Should do the trick. 1, followed by 0 or more of anything, followed by 1, and then 0 or more of anything with a 1.

This should occur anywhere within the string, so don't need to start at the start of the string, nor end with the end. And if there's more than 3 '1's, it'll still be true.

[biggiles]

tribbles said:

danpalmer1993 said:

I think this should work but it's been a while since I did any regex.

^(?:[^1]*1){3}[^1]*$

Seems a bit complicated, unless I'm missing something...

1.*1.*1

Should do the trick. 1, followed by 0 or more of anything, followed by 1, and then 0 or more of anything with a 1.

This should occur anywhere within the string, so don't need to start at the start of the string, nor end with the end. And if there's more than 3 '1's, it'll still be true.

I'd agree with Tribbles, this is a simple regex use case, no need to reach for ChatGPT for this one.