Discussion
Not sure if this is a daft question or simply a badly framed one.
How do you double a given temperature? Double 2 degrees Centigrade is 4? But if that is correct then what would double zero degrees be? Thinking about it in Kelvins doesn't seem to help either.
Or am I asking the wrong question?!
How do you double a given temperature? Double 2 degrees Centigrade is 4? But if that is correct then what would double zero degrees be? Thinking about it in Kelvins doesn't seem to help either.
Or am I asking the wrong question?!
toxicated said:
Not sure if this is a daft question or simply a badly framed one.
How do you double a given temperature? Double 2 degrees Centigrade is 4? But if that is correct then what would double zero degrees be? Thinking about it in Kelvins doesn't seem to help either.
Or am I asking the wrong question?!
Doubling a temperature would have to be done with reference to absolute zero, 0K, so double 2ºC would be (275.15*2)=550.3K How do you double a given temperature? Double 2 degrees Centigrade is 4? But if that is correct then what would double zero degrees be? Thinking about it in Kelvins doesn't seem to help either.
Or am I asking the wrong question?!
I believe that technically it is proportional to the average kinetic energy of the particles.
P.S. When did this forum appear? I swear it wasn't here a minute ago
P.P.S Hurrah that it has though!
Zad said:
toxicated said:
Not sure if this is a daft question or simply a badly framed one.
How do you double a given temperature? Double 2 degrees Centigrade is 4? But if that is correct then what would double zero degrees be? Thinking about it in Kelvins doesn't seem to help either.
Or am I asking the wrong question?!
Doubling a temperature would have to be done with reference to absolute zero, 0K, so double 2ºC would be (275.15*2)=550.3K How do you double a given temperature? Double 2 degrees Centigrade is 4? But if that is correct then what would double zero degrees be? Thinking about it in Kelvins doesn't seem to help either.
Or am I asking the wrong question?!
I believe that technically it is proportional to the average kinetic energy of the particles.
P.S. When did this forum appear? I swear it wasn't here a minute ago
P.P.S Hurrah that it has though!
RE: double 0C, i can see how the OP thinks it's wrong because double 2c is 4c so how can 0 be higher, but actually double 2c if in kelvin as well would be 550.3k
Silent1 said:
Just so you know Kelvin is 273.15 not 275.15, but otherwise i'm in agreement.
RE: double 0C, i can see how the OP thinks it's wrong because double 2c is 4c so how can 0 be higher, but actually double 2c if in kelvin as well would be 550.3k
Yes, the OP was stating +º2C, hence 275.15KRE: double 0C, i can see how the OP thinks it's wrong because double 2c is 4c so how can 0 be higher, but actually double 2c if in kelvin as well would be 550.3k
Zad said:
toxicated said:
Not sure if this is a daft question or simply a badly framed one.
How do you double a given temperature? Double 2 degrees Centigrade is 4? But if that is correct then what would double zero degrees be? Thinking about it in Kelvins doesn't seem to help either.
Or am I asking the wrong question?!
Doubling a temperature would have to be done with reference to absolute zero, 0K, so double 2ºC would be (275.15*2)=550.3K How do you double a given temperature? Double 2 degrees Centigrade is 4? But if that is correct then what would double zero degrees be? Thinking about it in Kelvins doesn't seem to help either.
Or am I asking the wrong question?!
I believe that technically it is proportional to the average kinetic energy of the particles.
P.S. When did this forum appear? I swear it wasn't here a minute ago
P.P.S Hurrah that it has though!
2 + 273.15 = 275.15 kelvin (absolute temp)
275.15 x 2 = 550.3 kelvin. Then take away the 273.15 to get the answer, ie 550.3 minus 273.15 = 277.15 degrees c, you just forgot to take off the 273.15 at the end.
To double zero, well convert zero to absolute temp ie 0 + 273.15 = 273.15, then double it.
Similary if you double 20 degrees F you get 499.67 (adding 459.67 to get absolute, not 460 which is usually shown).
Edited by Vipers on Wednesday 11th January 07:47
Further to my post, using Charles law if you double the temperature you will double the pressure, using same figures and a bottle of gas at 5 bars gauge, you will find the resulting answer to be a tad under 11 bars.
The reason it is 11 and not 10, 5 bars is 6 bars absolute, double that and you get 12 bars absolute, take one away and you get 11 bars gauge.
Dont forget to work in absolute pressure in this formulae.
Oh my ed hurts, time for a t break......
By the way, we don't bother about this stuff up here in Aberdeen, either its Cold, or bloody cold.
The reason it is 11 and not 10, 5 bars is 6 bars absolute, double that and you get 12 bars absolute, take one away and you get 11 bars gauge.
Dont forget to work in absolute pressure in this formulae.
Oh my ed hurts, time for a t break......
By the way, we don't bother about this stuff up here in Aberdeen, either its Cold, or bloody cold.
Edited by Vipers on Wednesday 11th January 07:49
Edited by Vipers on Wednesday 11th January 10:22
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