Can this tyre be repaired and, if so, would you?
Discussion
Andyjc86 said:
Without seeing it in person I would say no, it looks like the damage is too close to the side wall so the patch won't fit.
If the patch will fit then it depends on the amount of tread that's left and how much a new tyre is as to wether it's worth it.
Thanks!If the patch will fit then it depends on the amount of tread that's left and how much a new tyre is as to wether it's worth it.
I edited the original thread to add that the shoulder of the tyre to the nearest edge of the head of the nail is 10mm
http://www.etyres.co.uk/glossary-tyre-terms?term=t...
Link above gives law on area of tyre that can be repaired.I would probably say that is borderline as to if that could be repaired or indeed if any tyre shop would repair it.
redtwin said:
If the tyre repairer is OK with it I would be. The head of the nail may be significantly larger than the shank which would mean the hole is not that bad.
That said there are may numb nuts in tyres garages so go somewhere reputable, I used to sell tyres and a guy from my supplier of part worns said he would repair sidewall punctures if I wanted.... Errr no thanksLittle diagram here should help:
http://www.etyres.co.uk/glossary-tyre-terms?term=t...
Work out the area "t" on your tyre then go measuring
http://www.etyres.co.uk/glossary-tyre-terms?term=t...
Work out the area "t" on your tyre then go measuring

So, according to the diagrams on etyres
repairable area (T) = 70% of the nominal section width
In this case the tyre is a 265 so that's T = 185.5, leaving 79.5 / 2 = 39.75mm as the distance from either edge that can't be repaired.
This 'injury'is 10mm from the shoulder, i.e. 29.75mm too close to be repaired. And that's assuming the hole is less than 6mm (sure it is).
Any problem with those sums?
repairable area (T) = 70% of the nominal section width
In this case the tyre is a 265 so that's T = 185.5, leaving 79.5 / 2 = 39.75mm as the distance from either edge that can't be repaired.
This 'injury'is 10mm from the shoulder, i.e. 29.75mm too close to be repaired. And that's assuming the hole is less than 6mm (sure it is).
Any problem with those sums?
JPJPJP said:
So, according to the diagrams on etyres
repairable area (T) = 70% of the nominal section width
In this case the tyre is a 265 so that's T = 185.5, leaving 79.5 / 2 = 39.75mm as the distance from either edge that can't be repaired.
This 'injury'is 10mm from the shoulder, i.e. 29.75mm too close to be repaired. And that's assuming the hole is less than 6mm (sure it is).
Any problem with those sums?
Sounds about right to me. repairable area (T) = 70% of the nominal section width
In this case the tyre is a 265 so that's T = 185.5, leaving 79.5 / 2 = 39.75mm as the distance from either edge that can't be repaired.
This 'injury'is 10mm from the shoulder, i.e. 29.75mm too close to be repaired. And that's assuming the hole is less than 6mm (sure it is).
Any problem with those sums?
JPJPJP said:
So, according to the diagrams on etyres
repairable area (T) = 70% of the nominal section width
In this case the tyre is a 265 so that's T = 185.5, leaving 79.5 / 2 = 39.75mm as the distance from either edge that can't be repaired.
This 'injury'is 10mm from the shoulder, i.e. 29.75mm too close to be repaired. And that's assuming the hole is less than 6mm (sure it is).
Any problem with those sums?
I think that "70%" is a general figure. The actual restriction on a repair will be the size of the "backing plate" on the plug that would be used. The plugs look like giant drawing pins, with a big wide head that gets "rubber welded" to the inside of the tyre. So the restriction will relate to centre of the hole being sufficiently far "in board" from the inside of the tyre wall such that the entire diameter of the head of the plug can lie flat. Nothing more scientific than that really.repairable area (T) = 70% of the nominal section width
In this case the tyre is a 265 so that's T = 185.5, leaving 79.5 / 2 = 39.75mm as the distance from either edge that can't be repaired.
This 'injury'is 10mm from the shoulder, i.e. 29.75mm too close to be repaired. And that's assuming the hole is less than 6mm (sure it is).
Any problem with those sums?
where you take it for repair should have what is known as a puncture ruler which has a line down middle whichc you aline with center or tyre and will have markings to tell you dependant on tyre width if its a legal cold repair or not. if not as mentioned above find you local hot vulc repairer as will be cheaper than a new tyre
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